class Solution(object):
    def matrixReshape(self, nums, r, c):
        """
        :type nums: List[List[int]]
        :type r: int
        :type c: int
        :rtype: List[List[int]]
        """
        h, w = len(nums), len(nums[0])
        if h * w != r * c:
            return nums

        ans = []
        for x in range(r):
            row = []
            for y in range(c):
                row.append(nums[(x * c + y) / w][(x * c + y) % w])
            ans.append(row)
        return ans






        """
            In MATLAB, there is a very useful function called 'reshape', which can reshape a matrix into a new one
            with different size but keep its original data.

            You're given a matrix represented by a two-dimensional array, and two positive integers r and c representing
            the row number and column number of the wanted reshaped matrix, respectively.

            The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversing
            order as they were.

            If the 'reshape' operation with given parameters is possible and legal, output the new reshaped matrix;
            Otherwise, output the original matrix.

            Example 1:

            Input:
            nums =
            [[1,2],
             [3,4]]
            r = 1, c = 4
            Output:
            [[1,2,3,4]]
            Explanation:
            The row-traversing of nums is [1,2,3,4]. The new reshaped matrix is a 1 * 4 matrix, fill it row by row by
            using the previous list.

        """
